x^2+27x=324

Solution for x^2+27x=324 equation:

x^2+27x=324

We move all terms to the left:

x^2+27x-(324)=0

a = 1; b = 27; c = -324;
Δ = b2-4ac
Δ = 272-4·1·(-324)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-45}{2*1}=\frac{-72}{2}
=-36
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+45}{2*1}=\frac{18}{2}
=9
$